# Line slope calculator 4x-y=15

**Straight line given by points A[4; 1] and B[5; 5]**

## Calculation:

**Slope-intercept form of line:**y = 4x-15

**Canonical form of the line equation:**4x-y-15 = 0

**Parametric form of the line equation:**

x = t+4

y = 4t+1 ; t ∈ R

**Slope:**m = 4

**Slope angle of line: φ =**75°57'50″ = 1.3258 rad

**X intercept:**x

_{0}= 3.75

**Y intercept:**y

_{0}= q = -15

**Distance line from the origin:**d

_{0}= 3.638

**The length of the segment AB: |AB| =**4.1231

**Vector: AB =**(1; 4)

**Normal vector: n =**(4; -1)

**Midpoint of the segment AB: M =**[4.5; 3]

**Perpendicular Bisector equation:**x+4y-16.5 = 0

**Vector OA = (4; 1) ; |OA| = 4.1231**

**Vector OB = (5; 5) ; |OB| = 7.0711**

**Scalar product OA .OB = 25**

**Angle ∠ AOB = 30°57'50″ = 0.5404 rad**